Page 1: Introduction and Initial Problems

This page introduces the exam format and presents the first two problems of the set.

Problem Instructions

The instructions emphasize the importance of showing detailed work and simplifying mathematical expressions. Students are advised against using correction aids to ensure the possibility of contesting any marking errors.

Problem 1: Function Family Analysis

The first problem introduces a function family fa(x) = a·x² + 3x² - 2 and asks students to: a) Investigate the symmetry for all real values of a b) Determine the inflection points when a = -1 c) Calculate the slope at a specific point for a = -3

Highlight: This problem tests students' ability to analyze function behavior across different parameter values, a key skill in Kurvendiskussion Aufgaben mit Lösungen Abitur.

Problem 2: Real-World Application

The second problem presents a real-world scenario modeling a flu outbreak in a school with 2000 students. The spread is modeled by the function f(t) = 0.002t⁴ - 0.127t³ + 2.02t² + 1, where t represents days and f(t) represents the number of sick students (multiplied by 100).

Students are asked to: a) Calculate when the number of sick students stops increasing and how many are sick at that point b) Determine when the number of sick students is decreasing most rapidly

Example: This problem demonstrates how Kurvendiskussion Aufgaben mit Lösungen ganzrationale Funktionen PDF can be applied to model and analyze real-world situations.

Page 2: Additional Problems and Graph Analysis

This page continues with more advanced problems and introduces graphical analysis tasks.

Problem 3: Mathematical Statements

Students are asked to evaluate the correctness of three mathematical statements and provide brief justifications: a) If there's a local extremum at x=b, then f'(b) ≠ 0 b) There are cubic functions with exactly one local extremum c) Every saddle point is also an inflection point

Vocabulary: A saddle point is a point on the graph of a function where the slope is zero in all directions but is neither a local maximum nor a local minimum.

Problem 4: Function Family with Parameter t

This problem introduces a new function family f(x) = x³ - 4t·x² + 4t²·x with t ∈ ℝ. Students must: a) Find the zeros of the function when t = -1 b) Determine t so that the function has a zero at x₁ = 6

Definition: Zeros of a function are the x-values where the function equals zero, also known as roots or x-intercepts.

Problem 5: Parameter Determination for Specific Behavior

Students are given the function family f(x) = x³ + 3x² + 3tx + 1 and asked to: a) Determine the value of t for which the function has exactly two points with horizontal tangents b) Provide a concrete example of a function satisfying this condition

Highlight: This problem combines Funktionsscharen Aufgaben with the concept of horizontal tangents, testing students' ability to manipulate parameters for specific function behavior.

Problem 6: Graphical Analysis

The final problem on this page requires students to determine missing graphs as accurately as possible and mark significant relationships. Two scenarios are presented: a) A graph showing f(x) and its derivative f'(x) b) A graph with a saddle point and a line with slope m = 1

Example: This graphical analysis task is crucial for developing skills in Kurvendiskussion Aufgaben e-Funktion and understanding the relationship between a function and its derivative.

Page 3: Detailed Solutions

This page provides detailed solutions to the problems presented on the previous pages.

Solution to Problem 1

The solution demonstrates the step-by-step process for analyzing the function family fa(x) = a·x² + 3x² - 2.

a) Symmetry analysis shows that the function is even (symmetric about the y-axis) for all real values of a.

b) For a = -1, the inflection points are calculated: W₁ (2|8) and W₂ (-2|8)

c) The slope at point P(2|3) for a = -3 is calculated as m = 15/11

Highlight: This solution exemplifies the thorough approach required in Kurvendiskussion Aufgaben mit Lösungen Klasse 11 PDF, showing each step of the calculation process.

Solution to Problem 2

The solution to the flu outbreak problem is presented in detail:

a) The maximum point (peak of the outbreak) is calculated to occur at approximately 15.94 days, with about 129,004 students sick at that time.

b) The point of steepest decline (where the number of sick students is decreasing most rapidly) is determined to be around 25.02 days.

Example: This solution demonstrates how to apply calculus concepts to analyze real-world scenarios, a key aspect of Kurvendiskussion Aufgaben mit Lösungen klasse 10 PDF.